Test: Difference between revisions
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$\sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} .$ | $ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $ | ||
Revision as of 12:26, 14 June 2018
Just a test user.
Testing math rendering:
$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $