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$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $
$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $
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Revision as of 19:42, 6 August 2019

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Testing math rendering:

$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $


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