Test: Difference between revisions
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$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $ | $ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $ | ||
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Revision as of 19:42, 6 August 2019
Just a test user.
Testing math rendering:
$ \sigma = \sqrt{\int_{-\infty}^\infty (x-\mu)^2 \, p(x) \, dx} . $